Thanks Drxx. Using the corrections to the clues whose entries penetrate the block of 9 cells, I get:-
First row: three identical letters
Second row: a pair of identical letters, plus one other
Third row: three identical letters
First column: three identical letters
Second column: a pair of identical letters
Third column: one letter
That makes 15 letters in total, because 6 of the cells are in both across and down entries. This is the impasse I had previously reached and I cannot see the way forward.