I hope I'm not making things more complicated than they already seem to be. I notice that the clue solutions to 1Ac / 1Dn and 5Ac / 5Dn begin with the same letters, as they would in a normal crossword (B & L respectively). Can I assume that something similar occurs at the other initial letter juncture in cell 23?
Clue solutions which match the number of cells available in the grid, and therefore contain letters which encode to another single letter are
-6 AC
-34 AC
-5 DN
-15 DN
- 20 DN
- 25 DN
My initial move will be to write out the alphabet and mark all the letters included in the solutions of the above clues with a number 1.
The word "different" in the preamble is concerning me, but I'm hoping that everywhere else in the grid where my (marked with 1) letters may occur, will also be filled with the same single encoded letter.
I will then move on to looking at letter patterns in the cold solved clues I have . Is this a method?