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Just finished the grid fill. I have no idea how you'd do it without a spreadsheet, using over 1500 rows!!
It would be nice to know how many nets we're looking for - clearly,
< 80/6 = 13.3...

If you have a full grid, you have a count of each digit. So the number of nets

That's weird -> apparent the less than or equal symbol breaks the parser.

If you have a full grid, you have a count of each digit. So the number of nets is less than or equal to the minimum count for a digit.

It seems there are 11 possible distinct nets for a cube in geometry. Not sure if they're all here – still working on it.

I found the Catonmat tools extremely helpful for finding square, triangular, and prime numbers: https://catonmat.net/tools

Also, CalculatorSoup for multiples: https://www.calculatorsoup.com/calculators/math/multiples.php

Thanks buzzb ...missed that in the preamble!

I'm not a fan of the numericals, and as usual made heavy weather of this one. I'm pretty sure I've got the right grid fill. The coincidence of the maximum possible number of nets in the grid (from counting digits) and the number of net shapes tempts me to spend yet more time grid staring -- I'm only up to 8 so far.

I think I've found nine distinct dice nets. Not sure if that's all of them?

I'm now up to ten nets.

With a bit of rejigging, I've got 11.

Bunty, another thing. Once you have set up a spreadsheet, you can search for a string eg 463 or 443 from edit;find