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OK, thanks buzzb, glad it's all resolved.

The multipliers are 1 for 33a (palindrome), 4 for 11d and 9 for 22d

Oh goodness, having spotted 10 & 23 being double entries, before even beginning to solve, I promptly forgot it. Thanks so much, Buzzb. Perhaps I'm not so far wrong after all...

I think the 's' property description is fair. It says for each entry the multiplier is different. That doesn't preclude having the same multiplier for the grid numbers.

I am unsure of 35ac. I think it has property m and is 9?4.

Silly me

Having seen all the initial debate about the preamble here and elsewhere I decided just to batten down the hatches and crack on with it with the added bonus of missing yesterday's tedium (I mean the football natch!). Finally crawled over the line thanks in no small part to MS Excel which I find incredibly useful for cracking numerics as I am utter dunce otherwise.

The only thing that mystifies me in the comments is why 10a should have a "middle term 54", as my answer which I am very happy with has no such thing. Was this a typo or should I re-check?

I seem to have gone wrong on my allocation of type o answers. I have 2 and 20, but I should have a third. I hope this doesn't mean a restart.