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Oops. No wonder I was puzzled!

one cell to go be grateful for the type of clue for 10d/13a

Thanks

Don,
My very tentative answer is that 10d is type g and 13 type f. But I haven't quite finished and I may end up having to revise that. Two such answers certainly fit in my NW corner.

i think you are right - mine are anagrams of each other.

Thanks

That's what I have.

I'm stuck on 21d and 29a. I think 29 is type f. I thought 21 was type g but I can't get anything to fit of that type.

You are correct on both counts, 29a is a palindrome.

29a is palindrome, so complies with property (s), but otherwise these both associate with property (f) How are they duplicates buzzb ?

Some help, please.
After almost 2 hours I really seemed to be making inroads and had about half the grid filled. My problem became apparent when I ran out of possible locations for the tetrahedral number.
I'll try to explain how that happened.
I originally had 1, 4, 10, 20 & 35 as possible locations. 1&4 were discounted due to powers allocations, I have 10 as one of the locations for triangular numbers. So I had 20 & 35 remaining.
For property 'm' I had possible locations 14, 34, 35 & 38; for property 'o' I had possible locations 2, 14, 20 & 35. A total of 6 locations are required for those 2 properties, which means that all of those locations would be used for 'm' & 'o'...

The preamble states that each property describes the entry's grid number. But regarding property s there is no grid number whose reverse is divisible by that number.

11, 22, 33 ?