Crossword Help Forum
Forum Rules

gitto - did you see my second post. That assertion is wrong

AAH! Thanks CD, I'll persevere.

I should qualify my last post-any number that is not a palindrome(obviously not allowed anyway),or contains a zero,will be divisible by 11 when added to its reverse

earmaniac .. you are only talking about 2 digit numbers, aren't you?

In reply to Caphrist (#10), there are some tables available that may be helpful (which I bookmarked following the forum discussion of Listener 4751), available here: https://www.crossnumbersquarterly.com/. Look for 'CQ Tables.pdf', about two-thirds of the way down the page.

Jordan -yes only 2 digit

Still struggling like crazy here!! To see if I need to start again could someone please let me know if the sum of the digits in the final column is 3 higher than those in the 2nd column and 7 higher than those in the 2nd row?

No. I agree that the second column total is 4 higher than the second row total. But your final column sounds wrong to me. Of course, I could be wrong

Looks like I will have to start again, again. I assumed my 2nd columns and rows were correct and deleted everything else. I then reworked the grid on that assumption and came to the same result for the final column, so my difference of 4 must have been a fluke.

Jordan and earmaniac - 4 digit sums will also be divisible by 11. This is not necessarily the case for the 3 and 5 digit sums.