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the word you need for bargain is in Bradford's

That's exactly what i have demeter. No idea if they have any significance.

Thanks monkjunk.

Various points.
I agree with Cockie's comment #7, the puzzle isn't balanced.

MandyRob, the outer ring is a 4-letter word including a hole, opposite of subtract; then synonym of Robs minus T; then 3-letter sailor inside a source of formic acid (3,3) also including a hole.

I forget who it was, but someone made a very strong argument for 10-7, in that if 13 and 14 hadn't both been the same direction they would surely need to be counted individually.
And like others (I suspect) I don't have all the extra letters. In fact I only have 2F(?), 5C, and 6D. But perhaps it doesn't really matter, or maybe it does if the ring values are to be used as coefficients in the scoring system (which would make sense...in which case what would be the coefficient for the centre circle ?)

Demeter
I agree. Just remains to decide which number system is required when submitting answer! Show both I suppose - unless I am missing something in preamble.

Meursalt - you need to avail yourself of an older numbering system, let us say, for ring 2 and the centre continues the sequence.
If one views the grid as a target the common hole for 13 and 14 surely came from a single shot so a single score.

sorry - Meursault.

For Ring 2, I had 'V' from vail, rather than fail, but perhaps it could be either. I also had assumed that the ring values were to be used as coefficients and that the value of the centre was to be deduced: "...the sequence will enable a missing value to be identified".

demeter - I have 111110100 less than you for inward. Are you counting one twice?

carpox, I assumed the sequence to be something much simpler than coefficients and it seemed to work.